广西省桂林市、百色市2009年中考数学试题(含答案).pdf
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广西省桂林市、百色市2009年中考数学试题(含答案).pdf
- 1 - 2009 年桂林市、百色市初中毕业升学考试试卷 数学 (考试用时:120 分钟满分:120 分) 注意事项: 1本试卷分选择题和非选择题两部分在本试卷上作答无效 2考试结束后,将本试卷和答题卷一并交回 3答题前,请认真阅读答题卷上的注意事项 一、选择题 (共 12 小题,每小题3 分,共 36 分在每小题给出的四个选项中只有一项是符 合要求的, 用 2B 铅笔把答题卷 . 上对应题目的答案标号涂黑) 1 8- 的相反数是() A8-B8C 1 8 D 1 8 - 2下面的几个有理数中,最大的数是() A2B 1 3 C 3D 1 5 - 3如图,在所标识的角中,同位角是() A1和2B1和3 C1和4D2和3 4右图是一正四棱锥,它的俯视图是() ABCD 5下列运算正确的是() A22abab+=B 222 ()aba b-=C 2 a· 2 a= 2 2aD 42 2aa÷= 6二次函数 2 (1)2yx=+ 的最小值是() A2B1C 3D 2 3 7右图是一张卡通图,图中两圆的位置关系是() A相交B外离C内切D内含 8已知 2 1 x y = ? ? = ? 是二元一次方程组 7 1 axby axby += ? ? -= ? 的解,则ab-的值为() A1B 1C2D3 9有 20 张背面完全一样的卡片,其中8 张正面印有桂林山水,7 张正面印有百色风光,5 张正面印有北海海景;把这些卡片的背面朝上搅匀,从中随机抽出一张卡片,抽中正面是桂 1 2 3 4 (第 3 题图) (第 4 题图) (第 7 题图) - 2 - 林山水卡片的概率是() A 1 4 B 7 20 C 2 5 D 5 8 10如图,ABCD中,AC、BD为对角线,BC=6, BC边上的高为4,则阴影部分的面积为() A3B6C 12D24 11如图所示,在方格纸上建立的平面直角坐标系中, 将ABO绕点O按顺时针方向旋转90° , 得A B O,则点 A 的坐标为() A (3,1)B (3,2) C (2,3)D (1,3) 12如图 ,正方形ABCD的边长为 2,将长为 2 的线段QR的两端放 在正方形的相邻的两边上同时滑动如果Q点从A点出发,沿 图中所示方向按ABC D A滑动到A止,同时点R从B点 出发,沿图中所示方向按BC D AB滑动到B止,在这个 过程中,线段QR的中点M所经过的路线围成的图形的面积为 () A2B4 - C D 1- 二 填空题 (共 6 道小题,每小题3 分,共 18 分, 请将答案填在答题卷上) 13因式分解: 2 3xx+= 14据统计,去年我国粮食产量达10570 亿斤,用科学记数法表示为亿斤 15如图,在一次数学课外活动中,测得电线杆底部B与钢缆固定 点C的距离为4 米,钢缆与地面的夹角为60o,则这条钢缆在电 线杆上的固定点A到地面的距离AB是米 (结果保留根号) 16在函数21yx=-中,自变量x的取值范围是 17如图,是一个正比例函数的图像,把该图像 向左平移一个单位长度,得到的函数图像的 解析式为 18如图,在ABC中,AABC与ACD的 平分线交于点A1,得A1;A1BC与A1CD的平分线相 交于点A2,得A2; ;A2008BC与A2008CD的平 分线相交于点A2009,得A2009则A2009 A D C B 第 3 题图 x y 1 2 4 3 0-1-2-3123 A B 第 11 题图 A BC Q R M 第 12 题图 D 第 15 题图 A BC O y x 第 17 题图 2 - 1 B A CD 第 18 题图 A1 A2 - 3 - 三、解答题 (本大题共8 题,共 66 分, 请将答案写在答题卷上 ) 19 (本题满分6 分)计算: 101 ( )(20093)4sin30 2 - -+ o 2- 20 (本题满分6 分)先化简,再求值: 2211 () 22 xy xy xxyx + -+ + , 其中 23xy=, 21 (本题满分8 分)如图:在等腰梯形ABCD中,ADBC,对角线AC、BD相交于O (1)图中共有对全等三角形; (2)写出你认为全等的一对三角形,并证明 A D O C B 第 21 题图 - 4 - 22 (本题满分8 分) 2008 年 11 月 28 日,为扩大内需,国务院决定在全国实施“ 家电下 乡” 政策第一批列入家电下乡的产品为彩电、冰箱、洗衣机和手机四种产品某县一家 家电商场,今年一季度对以上四种产品的销售情况进行了统计,绘制了如下的统计图, 请你根据图中信息解答下列问题: (1)该商场一季度彩电销售的数量是台 ( 2) 请补全条形统计图和扇形统计图 23 (本题满分8 分)在保护地球爱护家园活动中,校团委把一批树苗分给初三(1)班同 学去栽种 如果每人分2棵,还剩 42 棵;如果前面每人分3 棵,那么最后一人得到的树 苗少于 5 棵(但至少分得一棵) (1)设初三( 1)班有 x名同学,则这批树苗有多少棵?(用含x的代数式表示) (2) 初三( 1)班至少有多少名同学?最多有多少名 数量 (台) 200 150 100 50 彩电洗衣机冰箱手机品种 手机 40%洗衣机 冰箱 20% 彩电 - 5 - 24 (本题满分8 分)在我市某一城市美化工程招标时,有甲、乙两个工程队投标经 测算:甲队单独完成这项工程需要60 天;若由甲队先做20 天,剩下的工程由甲、乙合做 24 天可完成 ( 1)乙队单独完成这项工程需要多少天? ( 2)甲队施工一天,需付工程款3.5 万元,乙队施工一天需付工程款2 万元若该工程 计划在 70 天内完成, 在不超过计划天数的前提下,是由甲队或乙队单独完成该工程 省钱?还是由甲乙两队全程合作完成该工程省钱? 25 (本题满分10 分)如图,ABC内接于半圆,AB是直径,过A作直线MN, 若MAC=ABC (1)求证:MN是半圆的切线; (2)设D是弧AC的中点,连结BD交AC于G, 过D作DEAB于E,交AC于F 求证:FDFG ( 3)若DFG的面积为4.5,且DG=3,GC=4, 试求BCG的面积 M N A E D C G B 第 25 题图 F - 6 - 26 (本题满分12 分)如图,已知直线 3 :3 4 lyx=+ ,它与 x轴、y轴的交点 分别为A、B两点 (1)求点A、点B的坐标; (2)设F是x轴上一动点,用尺规作图作出P,使P经过点B且与x轴相切于点F (不写作法和证明,保留作图痕迹); (3)设( 2)中所作的P的圆心坐标为P(xy,) ,求y与x的函数关系式; (4)是否存在这样的P,既与 x轴相切又与直线l相切于点 B,若存在,求出圆心P 的坐标;若不存在,请说明理由 x A B V F O · y 第 26 题图 - 7 - 2009 年桂林市、百色市初中毕业升学考试 数学参考答案及评分标准 一、选择题: 题号123456789101112 答案BACCBADBCCDB 二、填空题: 13(3)x x +141.057 ×10 4 154 316x 1 2 17 22yx= - 或 2(1)yx= -+ 18 2009 2 三、解答题: 19解:原式 =2-1+4 ×1 2 -2 ·····························································································4 分 =1··············································································································6 分 20 解: 原式 111 ()() 22 xy xyxy xxyxyx + =-+-? + ···············································2分 11 22 xy xx =-()·······························································································3分 ()xy= -···········································································································4 分 yx=- ··················································································································5 分 把23xy=,代入上式,得原式32-··························································6 分 21解: (1)3 3 分 (写 1 对、 2 对均不给分) (2)ABCDCB························································································4 分 证明:四边形ABCD是等腰梯形 AB=DC,ABC=DCB·································································6 分 又BC=CB ABCDCB··············································································8分 (注:选其它两对证明的,按以上相应步骤给分,全等三角形对应点不对应不扣分) 22解( 1) 150 ····································································································(2 分) (2)10% ······································································································(2 分) (3)每正确补全一个图形给2 分,其中扇形统计图每补全一个扇形给1 分 数量 (台) 200 150 100 50 彩电洗衣机冰箱手机品种 手机 40%洗衣机 冰箱 20% 彩电 30% 10% - 8 - 23解( 1)这批树苗有( 242 x+ )棵 ·········································································1 分 (2)根据题意,得 2423(1)5 2423(1)1 xx xx +- ? ? +- ? ···························································5分 (每列对一个不等式给2 分) 解这个不等式组,得40x44···········································································7 分 答:初三( 1)班至少有41 名同学,最多有44 名同学 ················································8分 24解:(1)设乙队单独完成需x天··············································································1分 根据题意,得 111 20()241 6060x ×+×=···················································3分 解这个方程,得 x=90·················································································4 分 经检验,x=90 是原方程的解 乙队单独完成需90 天·············································································5 分 (2)设甲、乙合作完成需y天,则有 11 ()1 6090 y+= 解得36 y= (天) ······························································································6 分 甲单独完成需付工程款为60×3.5=210 (万元) 乙单独完成超过计划天数不符题意(若不写此行不扣分) 甲、乙合作完成需付工程款为36(3.5+2 )=198(万元) ·····································7分 答:在不超过计划天数的前提下,由甲、乙合作完成最省钱···························8 分 25证明 (1) :AB是直径 ACB=90o ,CAB+ABC=90o·····················································1 分 MAC=ABC MAC+CAB=90o,即MAAB MN 是半圆的切线·································2 分 (2)证法 1: D是弧AC的中点,DBC=2··········3 分 AB是直径,CBG+CGB=90o DEAB,FDG+2=90o··················4 分 DBC=2,FDG=CGB=FGD FD=FG·····················································5分 证法 2:连结AD,则 1=2····························3分 AB是直径,ADB=90o 1+DGF=90o 又DEAB 2+FDG=90o·······························································4 分 FDG=FGD, FD=FG································································5分 (3)解法 1: 过点F作FHDG于H,·····························································6 分 又DF=FGSFGH= 1 2 SDFG= 1 2 ×4.5= 9 4 ·············································7分 AB是直径,FHDGC=FHG=90o············································8 分 HGF=CGB,FGHBGC M N A E D C G B 2 F H 3 1 - 9 - 221.59 ()() 464 FGH BGC SHG SCG ? ? =·····························································9分 SBCG= 964 16 49 ×=··············································································10 分 解法 2:ADB=90o,DEAB, 3=2····················································6 分 1=2, 1=3 AF=DF=FG······················································································7 分 SADG=2SDFG=9··················································································8分 ADG=BCG,DGA=CGB ADGBCG···············································································9 分 22416 ()( ) 39 BCG ADG SCG SDG = SBCG= 16 916 9 × = ·············································································10 分 解法 3:连结AD,过点F作FHDG于H, SFDG= 1 2 DG×FH= 1 2 ×3FH=45 FH=3···································································································6分 H是DG的中点,FHAD AD=2FH=6 ··························································································7 分 SADG= 11 639 22 AD DG?=× × =··························································8 分 (以下与解法2 同) 26解( 1)A( 4- ,0) ,B(0,3)·············································2 分(每对一个给1 分) (2)满分3 分其中过F作出垂线1 分,作出BF中垂线 1 分,找出圆心并画出P给 1 分 (注:画垂线PF不用尺规作图的不扣分) (3)过点P作PDy轴于D,则PD= x,BD=3y- ,···········6分 PB=PF=y,BDP为直角三形, 222 PBPDBD=+ 222 BPPDBD=+ ·····························7 分 即 222 3yxy=+- 即 222 (3)yxy=+- y与x的函数关系为 213 62 yx=+ ··········································································8 分 (4)存在 y x O A B DP F - 10- 解法 1:P与x轴相切于点F,且与直线l相切于点B AB AF= ················································································································9分 2222 5ABOAOB=+= 22 5AF= AF=4x+, 22 (4)5 x+ =············································································10分 19xx= -或········································································································11 分 把19xx= -或代入 2 13 62 yx=+,得 5 15 3 yy=或 点P的坐标为( 1, 5 3 )或(-9,15) ···································································12分