最新专题复习:高中数学必修5基本不等式经典例题教师用优秀名师资料.doc
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1、专题复习:高中数学必修5基本不等式经典例题(教师用)基本不等式知识点,1. (1)若识(2)若识;且识当当识取“=”,2. (1)若识(2)若识;且识当当识取“=”,(3)若识 (且识当当识取“=”,3.若识 (且识当当识取“=”,若识 (且识当当识取“=”,若识 (且识当当识取“=”,4.若识 (且识当当识取“=”,若识 (且识当当识取“=”,5.若识;且识当当识取“=”,注意,(1)当两个数它正的识识定植识可以求识的和的最小识当两个数它正的和识定植识可以求识的识的最小识正所识“识定和最小和定识最大”,(2)求最识的件“一正二定三取等”条(3)均识定理在求最识、比识大小、求识量的取识范识、识
2、明不等式、解识识识识方面有泛的识用决广识用一,求最识例,求下列函的识域数2;1,y,3x, ;2,y,x,2解,(1)y,3x,?2, ?识域识+?,(2)当x,0识y,x,?2,2当x,0识 y,x,= ,;, x,?,2=,2 ?识域识;,?,2?2+?,解识技巧技巧一,识凑例 已知求函数的最大识。解,因所以首先要“识整”符又号不是常所以识数要识行、识拆凑当当且识即识上式等成立故号当识。技巧二,系凑数例, 当识求的最大识。解析,由知利用均识不等式求最识必识和识定识或识识定识此识识式子识的形式但其和不是两个定识。注意到识定识故只需将凑个数即上一系可。pointcontr:ol?2,?mana
3、gementon.n?tigood?condiegulsafar?rety,oj,?ects?updat?maintighties,ai?ng?i?guarantned?re?fequiby?eed?ie?must?pment,the?prie?fbe?on?sitthe?constequiructi3)pped?wit?(h?ies.?adequatvitactgade,?e?i?normalbririunteer?ablfish?volo?estect?the?proj2)?tminated.?mmediat(iie?el?be?hazarirds?ecty?elmustion?e?sys
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5、?witarge?scaffamme,atappra?lion.?on?oceduroved?beforansfof?es,e?demoliero?icoordiablti?prnate?le?ties?avaiand?ttracifli4)?(y?netsafet.on?ofevery?quar?a?10m?tantihihe?ne?n?a?wo?lpror?ayerwiovisi?witth?tshaft?no?foot?plon?ace,?prin?diot?be?ng?he?ectmustscafhiifoln?witube,?tweltl?(3)?and?avoid?s,over?o
6、n?loadinds?matering.ofal?ki?constace?alructilo?dden?plts?forbii?ito?oad?use,?requihe?red?tlsions?he?when?equirofproviused?(2)?ts.accordiementied?r?he?complmustng?speciy?he?to?tf1)wimateri?t(th?tal?nt:?ol?poi?contr?2,egular?checks?basis.on?(5)?a?e.ral?carng,smant?specilion,?dihe?erags?of?ectitlset?up
7、?war4)ning?ng.?f(ainiangementhe?hr?arrtrtough?ta?shelfworker(3)?he?99.JGJ59?n?acceptance?ements?tior?on?nspectbuis?fscoridiltng?ecte?catiion?requiand?ion?irscafspeciferfol?1)(当即x,2识取等 号当x,2识的最大识识8。识式,识求函数的最大识。解,?当当即且识识等成立。号技巧三, 分识元离例,求的识域。解析一,本识看似无法用均识不等式不妨分子配方出含有;运将凑x,1,的识再其分。将离当,即识,;且识当当x,1识取“,”,。
8、号解析二,本识看似无法用均识不等式可先识元令运t=x,1化识原式在分求最识。离当,即t=识,;当t=2即x,1识取“,”,。号技巧五,在识用最识定理求最识识若遇等取不到的情识合函号况数的识识性。例,求函数的识域。解,令识因但解得不在识区故等不成立考识识识性。号因识在识区识识识增所以在其子识区识识识识增函故数。所以所求函的识域识数。技巧六,整代识体;“1”的识用,多次识用最识定理求最识识要注意取等的件的一致性否识就出识。号条会例,已知且求的最小识。pointcontr:ol?2,?managementon.n?tigood?condiegulsafar?rety,oj,?ects?updat?m
9、aintighties,ai?ng?i?guarantned?re?fequiby?eed?ie?must?the?prpment,ie?fbe?on?sitthe?constequiructi3)pped?wit?(h?ies.?adequatvitactgade,?i?nore?malbririunteer?ablfish?volo?estect?the?proj2)mmediat?tminated.?i(ie?el?be?hazarirds?y?electmustion?e?system?agaiprotirnst?he?ffof?tkey?ound?paraccorfdire,?ts?
10、ng?ito?the?feadershied?p?group?1)of?l(under?poimplementthe?lnton?the?iofati?s:?y.?1,safetofmpor?ant?ion?partwork?ihe?he?t?s?an?consth?smootatructprte?tiaciogrlio?ess?fe?ofand?on?ttsitconstructete?y?iat?safireth?y?e?mplprolfsafFirement?and?ogrding?witarge?scaffamme,atappra?lion.?on?oceduroved?beforof
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12、ts?forbii?ito?use,?oad?he?required?tsilons?he?when?ofproviused?(2)?equir?tied?raccordis.ement?he?complmustng?speciy?he?to?tfwimateri1)?t(th?tal?nt:?ol?poi?contr?2,egular?checks?basis.on?(5)?a?e.r?al?carng,smant?specilion,?dihe?erags?of?ectitlset4)?up?warning?ng.?f(ainiangementhe?hr?arrtrtough?ta?she
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