最新数学作业本九上答案(The+math+exercise+book,+nine+answers)优秀名师资料.doc
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1、数学作业本九上答案(The math exercise book, nine answers)数学作业本九上答案(The math exercise book, nine answers) Chapter 1 inverse ratio function 1.1 (1) 1., no yes, yes, yes, no, / /, 3, 1/2, - pi, /. 2.x = 0 for all real, 1/4, -1 3., the answer is not unique. If the function argument is y = 12/x, there are: (1) 3 (
2、2) 3/2 (3) -3/2 4. (1) v = 240/t (2), when t = 3.2h, v = 75km/h 5. (1) S = 600/x (2) a = 300/b 6. (1) a = 16/h, H takes more than 0 of all real numbers (2) the upper and lower bottom and 8cm, waist AB = CD = 2 V 2cm, trapezoidal circumference (8+4 * 2) cm 1.1 (2) 1.-12 2.y = 10/x, x = 0 for all real
3、 3.y = 6/x. x = V - V when y = 6, -1 4. (1) y = 2Z, z = -3/x (2) x = -3/5, y = 10 (3) y = -6/x, yes 5. (1) D = 100/S (2) 150 degrees 6. (1) y = 48/x, is the scale factor 48, the practical significance is that the rectangular area of the group is 48cm2 (2) one side of the rectangle is a (CM), and the
4、 other side is 3A (CM). The x = a, y = 3A is substituted by y = 48/x, and a = 4, so the perimeter of the rectangle is 2 (a+3a) = 32 (CM) 1.2 (1) 1.y = - V 2/x 2.B 3. (1) table slightly (2) at the 4. (1) y = 4/x (2) at the The analytic formula of 5. (1) inverse scaling function is y = 8/x, and the co
5、ordinate of one intersection point is (2, 4), and the coordinate of the other intersection point is (-2, -4) 6. according to the problem it 3m-1 0, 1-m 0, 1/3 m 1 solution 1.2 (2) 1., two, four; increase 2.C 3.m x 0, or X 5. (1) t = 6/v (2) 18km/h 6. (1) y = -2/x, y = -x-1 (2) x -2 or 0 x 1 1.3 1.D
6、2.y = 1200/x 3.r = 400/h, 20 4. (1) y = 2500/x (2) 125m 5. (1) t = 48/Q (2) 9.6m3 (3) 4H 6. (1) of image can not be displayed, select the inverse proportion function model to try. If the point (1, 95), P = 95/V. will be four points one by one into the other coordinate validation shows that P = 95/V
7、is an analytic function for (2) 63kPa (3) shall be no less than 0.7m3 *7. (1) y = 14x+30, y = 500/x (2) substituting y = 40 into y = 14x+30 and y = 500/x, and getting x = 5/7 and x = 25/2, with a total operation time of 25/2-5/7 = 165/14 (points) review questions The 1. function is y = (-12) /x. poi
8、nt B. On the image of this function, the point C is not on the image 2. 3. function analysis is y = -3/x., the answer is not unique, such as (-3, 1), (-1, 3),. 4.y = -2/x, X axis 5. (1) Y2 Y1 Y1 Y3 6. (1) P = 600/S, the independent variable S range is S 0 (2) slightly (3) 2400Pa, at least 0.1m2 7.,
9、two, four 8.A (2, 4), M = 8 9. (1) by -2k2-k+5 = 4, K 0 K = -1.y = (-1) /x (2) M = 3 + V 10. (1) P (1, -3) into y = - (3m) /x, get m = 1, then the inverse function of the analytic formula is y = -3/x., the point P (1, -3) into y = kx-1, get k = -2, The analytic expression of the first function is y
10、= -2x-1 (2) y = -2x-1 = 0, the horizontal coordinate point P -1/2, POP for the delta area is 1/2 * |-1/2| * |-3| = 3/4 11. (1) coordinate points A for (-1, a), while the B coordinates of (1, -a). The area is 2 ADB, a = 2. can be obtained by analytical formula so for the two functions are y = -2/x, y
11、 = -2x (2) AD as the delta ADP, the abscissa when the P is -5 or 3, 4 is the delta area of ADP, so the P coordinate is (3, -2/3), (-5, 2/5) 12. AB above the X axis. Dreams AB = A B = |b|, BO = B O = |a|, ABO = Rt * Rt * A B O, OA r = OA, AOB / A / = OB . When the PQ is a three quadrant angle bisecto
12、r at well, / AOQ / A = OQ PQ AA is the star, so the image inverse proportion function in one, the three quadrant angle bisector symmetrical C The second chapter, the two function 2.1 1.B 2.y = -x2+25 pi 3.1, -2, -1; 3, 0, 5; -1/2, 0; 3, 2, 2, 1, 2 -4; -2 V, 1 4.y = -2/3x2+7/3x+1 5. (1) S = -1/2x2+4x
13、 (0 x 8) (2) 7/2, 8, 6 6. (1) y = (80+2x) (50+2x) = 4x2+260x+4000 (2) by D. 4x2+260x+4000 = 10800, X1 = -85 solution x2 = 20. (up), so the golden edge of the paper width is 20cm 2.2 (1) 1. parabola, Y axis, down, (0, 0), highest, below 2. of the 6, 3/2, 3/8, 0, 3/8, 3/2, 6; -6, -3/2, -3/8, 0, -3/8,
14、-3/2, -6 at the 3.y = 2x2, point (1, 2) on parabola 4. 5.y = -1/9x2. (-b, -ab), i.e. (1, -1/9), on a parabola 6. (1) y = -3/50x2 (2) substituting x = 5 for y = -3/50x2, and getting y = -1.5., then the water level reaches the warning line after 22.5 2.2 (2) 1. (1) left, 2, (2) on, 2 2. (1) open upwar
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