最新高二文科数学导数专项复习优秀名师资料.doc
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1、高二文科数学导数专项复习高二文科数学过关检测导学案(选修1-1第三章) 导数的概念及其运算是导数应用的基础,是高考重点考查的内容。考查方式以客观题为主,主要考查导数的基本公式和运算法则,以及导数的几何意义。导数的应用是高中数学中的重点内容,导数已由解决问题的工具上升到解决问题必不可少的工具,特别是利用导数来解决函数的单调性与最值问题是高考热点问题。选择填空题侧重于利用导数确定函数的单调性、单调区间和最值问题,解答题侧重于导数的综合应用,即与函数、不等式、数列的综合应用。 一、知识点梳理 (1) 平均变化率: 对于一般的函数yfx,,在自变量从变化到的过程中,若设, xxx,x,x,x,1221
2、则函数的平均变化率为 ,f,f(x),f(x)21(2)导数的概念 b,x一般的,定义在区间(,)上的函数,当无限趋近于x,(a,b)af(x)of(x,,x),f(x),yoo,0时,无限趋近于一个固定的常数A,则称在处x,xf(x)o,x,xf(x)|可导,并称A为在x,x处的导数,记作f(x)或 f(x)x,xooo(3)导数的几何意义 (,()xfx 函数y=f(x)在x=x处的导数等于在该点处的切线的 。 000基本初等函数的导数公式表及求导法则(默写) office, branch offices (jurisdiction), risk management, marketing
3、 management sector through supervision and inspection found problems, should be assigned the investigators are corrected in a timely manner. 27th the fifth chapter penalty under any of the following acts, then the relevant provisions to punish the investigators, according to the Bank. To constitute
4、a crime shall be investigated for criminal responsibility: (A) on the business that are not involved in the investigation, issued a survey. (B) customer credit information are not thorough verification. (Iii) to participate in credit customer survey is not in place, customers and data is incomplete,
5、 untrue; he knows bear a counterfeited clients issuing credit. (D) does not provide for due diligence of credit business, pre-loan investigation form, concealing facts or providing false information or should be found in a normal investigation failed to discover the risk factors, lead to the review
6、and approval policy errors, loan risk. (Five) on loan guarantees of survey not in place, not by provides on arrived, and pledge real for field verification, and assessment, and identification and registration, not according to provides on guarantor of guarantees qualification and guarantees capacity
7、 for survey verified, led to guarantees loan lost authenticity, and legitimacy, and effectiveness of; cycle loan business in the of mortgage (5)函数单调性与导数:在某个区间内,如果,那么函数在(,)abyfx,()fx()0,这个区间内 ;如果,那么函数在这个区间yfx,()fx()0,内 ( 说明:(1)特别的,如果,那么函数在这个区间内是常函yfx,()fx()0,数( (6)求解函数单调区间的步骤: yfx,()新疆王新敞奎屯(7)求可导函数f(
8、x)的极值的步骤: (1)确定函数的定义区间,求导数f(x) (2)新疆王新敞奎屯求方程f(x)=0的根(3)用函数的导数为0的点,顺次将函数的定义区间分成若干小开区间,并列成表格.检查f(x)在方程根左右的值的符号,如果左正右负,那么f(x)在这个根处取得极大值;如果左负右正,那么f(x)在这个根处取得极小新疆王新敞奎屯值;如果左右不改变符号,那么f(x)在这个根处无极值 (8)函数的最值与导数:一般地,在闭区间,a,b上函数的图像是一条连yfx,(),续不断的曲线,那么函数在a,b上必有 ( yfx,()二、典型例题 x1、曲线y,在点(1,,1)处的切线方程为 ( ) x,2A(y,x,
9、2 B(y,3x,2 C(y,2x,3 D(y,2x,1 2、函数y,xlnx在区间 ( ) 11(0,)(,,,) (A) 上单调递减 (B) 上单调递减 ee(0,,,)(0,,,) (C) 上单调递减 (D) 上单调递增 office, branch offices (jurisdiction), risk management, marketing management sector through supervision and inspection found problems, should be assigned the investigators are corrected
10、in a timely manner. 27th the fifth chapter penalty under any of the following acts, then the relevant provisions to punish the investigators, according to the Bank. To constitute a crime shall be investigated for criminal responsibility: (A) on the business that are not involved in the investigation
11、, issued a survey. (B) customer credit information are not thorough verification. (Iii) to participate in credit customer survey is not in place, customers and data is incomplete, untrue; he knows bear a counterfeited clients issuing credit. (D) does not provide for due diligence of credit business,
12、 pre-loan investigation form, concealing facts or providing false information or should be found in a normal investigation failed to discover the risk factors, lead to the review and approval policy errors, loan risk. (Five) on loan guarantees of survey not in place, not by provides on arrived, and
13、pledge real for field verification, and assessment, and identification and registration, not according to provides on guarantor of guarantees qualification and guarantees capacity for survey verified, led to guarantees loan lost authenticity, and legitimacy, and effectiveness of; cycle loan business
14、 in the of mortgage 2在x,2处有极大值,则常数的值为_; 3、若函数cfxxxc=-()(),x4、函数的一个单调递增区间是 ( ) f(x),x,e(A) (B) (C) (D) ,1,02,81,20,235、函数的极值是 f(x),x,12x6、已知函数y,f(x)的导函数y,f(x)的图象如下,则( ) A(函数f(x)有1个极大值点,1个极小值点 B(函数f(x)有2个极大值点,2个极小值点 C(函数f(x)有3个极大值点,1个极小值点 D(函数()有1个极大值点,3个极小值点 fx32x,17、已知在时取得极值,且( f(1),1f(x),ax,bx,cx(a
15、,0)?、试求常数a、b、c的值; x,1?、试判断是函数的极小值点还是极大值点,并说明理由( office, branch offices (jurisdiction), risk management, marketing management sector through supervision and inspection found problems, should be assigned the investigators are corrected in a timely manner. 27th the fifth chapter penalty under any of th
16、e following acts, then the relevant provisions to punish the investigators, according to the Bank. To constitute a crime shall be investigated for criminal responsibility: (A) on the business that are not involved in the investigation, issued a survey. (B) customer credit information are not thoroug
17、h verification. (Iii) to participate in credit customer survey is not in place, customers and data is incomplete, untrue; he knows bear a counterfeited clients issuing credit. (D) does not provide for due diligence of credit business, pre-loan investigation form, concealing facts or providing false
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