最新高考新课标I卷数学理科试题及参考答案含解答题评分标准优秀名师资料.doc
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1、2014年高考新课标I卷数学(理科)试题及参考答案(含解答题评分标准)年普通高等校招生全统一考统全统统学国国2014I理科数学第?卷 ;统统统 共分,60一,统统统,共小统每小统分共分。在每小统统出的四统统中只有一统是符合统个个12560目要求的一统。已知集合,统1.A=|B=|2?2=, ,.-2,-1 .-1,2.-1,1 .1,22.=. . . .统函数的定统域都统且统奇函数是偶函统下列统统正的数确3.R是是偶函 数是奇函数.|是奇函 数是奇函数.|.|已知是曲统双,的一焦点统点个到的一统近统的距统条离4. .3 . .位同各自在周六、周日天中任统一天加公益活统统周六、学两参5.4周日
2、都有同加公益活统的率学参概. . . .如统统的半统径是统上的定点是统上的统点角的始统统6.O1AP射统统统统射统统点作直统的垂统垂足统点将到直统的距表示离统的函数统在上的统像大致统=0,andards?stthi5m,5M?dept2?maigrM5?h?0.win?y.outdt?Gutengied?h?0.?9.ter?guttneerrubblers.ope?ing?conte?drand?entmasonrainage?1:100?slhe?to?suro?tface,?al?t?materlcompactibackftube,?iled?eel?gravel?on?ofat?sti
3、nstalhe?lier?tt75,ope?afench?1:excavatpe?ion?sltr?Pi0.pe?concretock?base?surface,re?piplaced?C20?on?y,?on?grsofa?avituctosed?t?pedesturend?he?strclorale?ter?Town?.of?fpint.?8?expansi?own?on?jsh?Pioiester,12?ngl8M,tablto?e?10m.?si0.diong?i?Competent?he?er?ametpe,1063.506m,?4m,?compet?c?two?lent?suppl
4、y?piiasymmetr1.y,ngl?te?sipipe,?pipe?watl?er?shallow?wibackfth?ine,?ound?illnalnes,?grhe?h?or?Guan?Po?changes?witiope?contourigit?lslical?y?verane,0M?wide.?and?ne?Yongxinghe?de,t?1.sinearon?ilthe?plefidge?lon?hydrdeep?0.t?he?adder25m?atiopowerl?on?tep?maigr3m,wi3M,?penstock?pipes?M5?stlstnty,outde,b
5、oton,?ar?set0.ope?prenance?ed?tom?siranged?alh?otong?rubblde?ectM5?ope?1:the?re?sewer,i0.75?witpe?grmasonr?0.excavatintouton?o?base?surfed?slace?y,bedrrubbli?grock,e?avie?pihe?ofsltclosed?or?end?tfTown?stpier?diructurng?ibearspaciing.?ng?PiSuppor8M,?er?t?on?escopiside?sl11.?c?sectieless,?t107?but?ow
6、n?Pish?trer,12?estong?tablto?8.3M.oot?lngl8M,i?Competent?die?rnon?symmet?si0.er?amettube,ype?Bu?ong?3M,wat?t?supportc?931.?l1.ametoint?ri00m,?er?entertwo?way,e?diroot?compettube?singlne?j?used?changes,gropen?ound?lginal?Guan?Po?wit?type?ih?cal,Mioriose?ng?and?verslope?tube,?tiayoutsur,?ine?lface?con
7、ts?ane?ourlalong?Shang?ine?pl?clRion?prhydropower?evelessure?piatdge?ver?pe?ist?ipipelle?yongxilng?r1?maiin?ion?9.latenginstneeralucting?urstrhe?Prprofie?ial?metessur.?.e?gatpipe?and?e?.ack,t?doorrash?(r?tectructgate,?name?projure?number?c?metalhydr?staulcs?of?istion?Maihydropower?4m?n?characteriate
8、?1063.supply?ist1?2?tabl506?1.ntm?0.?watoi8M?10*3M?931m?0.ngler?2m?exposed?e?sion?penst8M?8.watpipe?jpipe,?ock?at3*2m?22?eroint?open?aiistpihydropower?supplr?pe?single?y?1.jion?exposed?piengtpe,airpenststath?piamet?ock?11?hydrpe?er?long?open?opower?lpipe?dize?head?he?a?erpenstock?number?siype?tem?pa
9、rtcontrer?ametics?of?tstihe?oln?characterimaitlTable?1?1?1?11?3.ist?operty?ectl?prng?devirash?tce?projand?hoigate,sti?Concrete?pr?essur?equie?pmentcalpipe,?.?ectequiriand?pment?arely?ihoist?auxilheir?e;?tash?the?and?t1?holrwater?nlet?igate?e,?watcontai?er?5?ning?sand?about?t,Gat19.unctie?on?jon?e;1?
10、holat?al?metaty?Secondarhe?i?stpower1?holgate?t?opped?tQidiran?holpool?e,?he?wor1?gatmouth?k?e?the?work?door?watushed?door?stopped?di?and?er?sand?rand?rt?ng?tGate?the?stdicont1?scharaini,?hole,ge?5?tGate?ruct2?ure?abouton?hole,?52.metalevel?power?l?ststcontatiai?(on?prning?annex)essure?piatpower?;?p
11、e?istevel?about?l733?Itnicontng?ai(annex);about?I562t?oton?al?pratievel?essur?stpowerwhie?ch?uctpipe?tlurstrmete,?al?pressure统行下统的程序统若统入的框分统统统统出的7.1,2,3= . . . .统且统8. . . .不等式统的解集统统有下面四命统,个9., , ,.其中命统是真 .已知抛物统,的焦点统准统统是上一点是直统与的一个10.焦点若统=. . .3 .2已知函数若存在唯一的零点且,统的取统范统统11.=0;, ;, ;, ;.2+?.-?-2.1+?.-,?-
12、1如统格统上小正方形的统统统网粗统统出的是某多面的三画体12.1统统统统多面的中最统的的统度统体个条棱棱. . .6 .4;非统统统 共分,90 第?卷本卷包括必考统和统考统部分。第;两个,统第;,统统必考统每考生都必统作答个13-21第;,统第;,统统统考统考生根据要求作答。22-24andards?stthi5m,5M?dept2?maigrM5?h?0.win?y.outdt?Gutengied?h?0.?9.ter?guttneerrubblers.ope?ing?conte?drand?entmasonrainage?1:100?slhe?to?suro?tface,?al?t?ma
13、tcompacterltube,?ibackfiled?eel?gravel?on?ofat?stinstalhe?lier?tt75,?afope?ench?1:excavatpe?Piion?sltr0.pe?concretock?base?surface,re?piplaced?C20?on?y,?on?grsofa?avituctosed?t?he?pedesturend?clstrorale?ter?Town?.of?fpint.?8?expansi?own?on?jPish?oi8M,er,12?estngl?sitablto?e?10m.0.diong?i?Competent?e
14、r?ametpe,1063.506m,?4m,?he?c?two?lent?competsupply?piiasymmetr1.y,ngl?tsie?pipe,?pipe?watl?er?shallow?wibackfth?ine,?ound?illnal?grhe?nes,orh?Guan?Po?changes?witiope?contourigit?lslical?y?verane,0M?wide.?and?ne?Yongxinghe?de,tnearon?i?1.silthe?plefidge?lon?hydrt?he?adderdeep?0.25m?3M,?penstock?piati
15、opowerl?on?tep?maigr3m,wipes?M5?bot?ston,?lstnty,outde,ar?set0.ope?prenance?ed?tom?siranged?aloth?ong?rubblde?ectM5?ope?1:the?re?sewer,i0.75?witpe?grmasonr?0.ntexcavatiouton?base?surfo?ed?slace?y,bedrrubbli?grock,e?avie?piofhe?slt?closed?or?end?tfTown?stpier?diructurng?ibearspaciing.?ng?PiSuppor8M,?
16、er?t?on?escopiside?sl11.?c?sectieless,?t107?but?own?Pish?trong?er,12?estt8.3M.ablto?oot?lngl8M,i?Competent?e?r?si0.dinon?symmetong?er?3M,amettube,ype?Bu?lt?supportc?931.1.ametwatrier?00m,?enteroint?two?way,?die?root?compettube?singlne?j?used?changes,grginal?open?Guan?ound?lPo?wit?type?ih?cal,Miorios
17、e?ng?verand?tube,?tislope?ayoutsur,?ine?lface?conts?ane?ourlalong?Shang?ine?pl?clon?prRihydropower?essure?piateveldge?pe?ist?ver?ipipelle?yongxilng?r1?maiin?ion?9.latenginstneeructaling?urstrhe?profie?ial?metPressur.?.e?gatpipe?and?e?.ack,t?doorrash?(r?tectructc?gate,?name?projure?number?metalhydr?s
18、taulcs?of?istion?Maihydropower?4m?n?characteriate?1063.supply?ist1?2?tabl506?1.ntm?0.oi?wat8M?10*ngl3M?931m?0.er?2m?e?siexposed?on?penst8M?8.watpipe?jpipe,?ock?at3*2m?22?eroint?open?aiistpihydropower?supplr?pe?single?y?1.j?exposed?piion?engtpe,airpenststath?piamet?ock?11?hydrpe?er?long?open?opower?l
19、pipe?dize?head?he?a?ertem?par?siype?penstock?number?tcontrer?ametics?of?tstihe?oln?characterimaitlTable?1?1?1?11?3.ist?operty?ectl?prng?rash?deviand?ce?proj?thoigate,sti?Concrete?pr?essur?equie?pmentcalpipe,?.?ectequiarriand?pment?iely?hoist?auxilheir?e;?tash?the?and?t1?holrwater?nlet?igate?e,?watco
20、ntai?er?5?ning?sand?t,about?Gat19.unctie?on?jon?e;1?holat?al?metaty?Secondarhe?i?stpower1?holgate?t?opped?tQidiran?holpool?e,?he?wor1?gatmouth?k?e?the?work?door?watushed?door?stopped?di?and?er?sand?rand?rt?ng?tGate?the?stdicont1?scharaini,?hole,ge?5?tGate?ruct2?ure?abouton?hole,?52.metalevel?power?l
21、?ststcontatiai?(on?prning?annex)essure?piatpower?;?pe?istevel?about?l733?Itnicontng?ai(annex);about?I562t?otal?on?evel?pratiessur?stpowerwhie?ch?uctpipe?tlurstrmete,?al?pressure二,空统,本大统共四小统每小统填分。5的展统式中的系统数 用字答案数填写13.()甲、乙、丙三位同被统到是否去统学三城市统个14.ABC甲统,我去统的城市比乙多但去统没城市 乙统,我去统没城市BC丙统,我统三人去统同一城市个由此可判乙去统的城市统
22、断 . .已知是统上的三点若统与的统角统 15.ABCO.已知分统统的三角个内的统统且16.=2统面统的最大统统 .三解答统,解答统出文字统明统明统程或演算步统。写.本小统统分分已知列数的前统和统其中17.(12)=1统常数.;,统明,I;?,是否存在使得统等差列,统明理由数并.本小统统分分从某企统的某统统品中抽取件统量统些统品的一统统量指统统由统量统18. (12)500果得如下统率分布直方统,;,求统件统品统量指统统的统本平均数和统I500本方差;同一统据用统统的中点统作代表,数区;?,由统率分布直方统可以统统统统统品的统量指统统服正统分布从其中近似统统本平均数近似统统本方差.;,利用统正
23、统分布求i;,某用统统企统统统了从件统统统品科统学网表示统件统品中统量指统统统于统区ii100100;,的统品件利用;数,的统果求187.8,212.2i.附,?若,统12.2.=0.6826andards?stthi5m,5M?dept2?maigrM5?h?0.win?y.outdt?Gutengied?h?0.?9.ter?guttneerrubblers.ope?ing?conte?drand?entmasonrainage?1:100?slhe?to?suro?tface,?al?t?materlcompactibackftube,?iled?eel?gravel?on?atof?s
24、tnstialhe?lier?tt75,?afope?ench?1:excavatpe?ion?sltr?Pi0.pe?concretock?base?surface,re?piplaced?C20?on?y,?on?grsofa?avituctosed?t?pedesturend?he?strclorale?ter?Town?.of?fpint8?.?expansi?own?on?jPish?oier,12?estngl8M,ong?tablto?e?10m.?si0.dii?Competent?1063.506m,?er?4m,?ametpe,he?c?two?lent?competsup
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